Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Let a=3, b=4, c=5 and a×a×c+4b=0, then the value of a×c2 equals to
MathematicsVector AlgebraJEE Main
Options:
  • A 9256
  • B 163
  • C 2569
  • D 316
Solution:
1356 Upvotes Verified Answer
The correct answer is: 2569

a×a×c=-4baca-aac=-4b

Let, ac=accosθ
15cosθa-9c=-4b
15cosθa-9c2=16b2
225cos2θ×9+81×25-270×15cos2θ=16×16
2025cos2θ=1769
cos2θ=17692025
sin2θ=2562025
a×c2=a2c2sin2θ
a×c2=2569

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.