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Let $A=\{a, b, c, d\}$ and $B=\{x, y, z\} .$ What is the number of element in $A \times B$?
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The correct answer is:
12
$\mathrm{n}(\mathrm{A})=4$ and $\mathrm{n}(\mathrm{B})=3$
Number of elements in $n(A \times B)=4 \times 3=12$
Number of elements in $n(A \times B)=4 \times 3=12$
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