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Question: Answered & Verified by Expert
Let A=aij be a square matrix of order 3 such that aij=2j-i, for all i, j=1,2,3. Then, the matrix A2+A3++A10 is equal to
MathematicsMatricesJEE MainJEE Main 2022 (29 Jun Shift 1)
Options:
  • A 310-12A
  • B 310+12A
  • C 310+32A
  • D 310-32A
Solution:
1789 Upvotes Verified Answer
The correct answer is: 310-32A

Given, A=aij3×3 where aij=2j-i we get,

A=124121214121

 A2=124121214121124121214121

A2=3612323634323=3A  A3=3A2=9A

Now, A2+A3+A4+A10

=3A+32A+33A+39A

=3A39-13-1=A310-32

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