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Question: Answered & Verified by Expert
Let \(A, B\) and \(C\) be three angles of a \(\triangle A B C\) such that \(\cos A+\cos B+\cos C=\frac{3}{2}\), then the \(\triangle A B C\) is
MathematicsTrigonometric EquationsAP EAMCETAP EAMCET 2020 (18 Sep Shift 2)
Options:
  • A Equilateral
  • B Right angled
  • C Isosceles but not equilateral
  • D Scalene
Solution:
2610 Upvotes Verified Answer
The correct answer is: Equilateral
Given, \(\cos A+\cos B+\cos C=\frac{3}{2}\)
Above equation is possible only for \(A=B=C=\frac{\pi}{3}\)
\(\therefore \triangle A B C\) is equilateral,
Hence, option (a) is correct.

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