Let $A B C$ be a triangle. Let $u=\mathbf{A B}$ and $v=\mathbf{A C}$. If $D$ is a middle point of $B C$, then $\mathbf{A D}=$

Question

Let $A B C$ be a triangle. Let $u=\mathbf{A B}$ and $v=\mathbf{A C}$. If $D$ is a middle point of $B C$, then $\mathbf{A D}=$, $\frac{u-v}{2}$, $\frac{v-u}{2}$, $\frac{u+v}{2}$, $u+v$

MARKS App · Accepted Answer

If in a $\triangle A B C, \mathbf{A B}=\mathbf{u}$ and $\mathbf{A C}=\mathbf{v}$ and $D$ is mid-point of $B$ and $C$, then $\mathbf{A D}=\frac{\mathbf{A B}+\mathbf{A C}}{2}=\frac{\mathbf{u}+\mathbf{v}}{2}.\quad \{\text{mid-point formula} \}$

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