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Let $\bar{a}, \bar{b}, \bar{c}$ be such that $\bar{a} \neq \bar{o}, \bar{b} \neq \bar{o}, \bar{a} \times \bar{c}=\bar{b}$ and $\bar{b} \times \bar{c}=\bar{a}$. Then
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The correct answer is:
$|\bar{b}|=|\bar{a}|$
No solution. Refer to answer key.
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