Given expression is $2^{\mathrm{a}} 3^{\mathrm{b}} 5^{\mathrm{c}}$ in which $\mathrm{a}+\mathrm{b}+\mathrm{c}=5$ and $\mathrm{a}, \mathrm{b}, \mathrm{c}$ e.
Total number of combinations of $a, b, c$ to be a sum 5 . are $(1,1,3),(1,3,1),(3,1,1),(2,2,1),(1,2,2)$ and $(2,1,2)$ So,
$$
\begin{aligned}
& 2^1 \cdot 3^1 \cdot 5^3=6 \cdot 12 \cdot 5=750 \\
& 2^1 \cdot 3^3 \cdot 5^1=2 \cdot 27 \cdot 5=270 \\
& 2^3 \cdot 3^1 \cdot 5^1=8 \cdot 3 \cdot 5=120 \\
& 2^2 \cdot 3^2 \cdot 5^3=4 \cdot 9 \cdot 5=180 \\
& 2^1 \cdot 3^2 \cdot 5^2=2 \cdot 9 \cdot 25=450 \\
& 2^2 \cdot 3^1 \cdot 5^2=4 \cdot 3 \cdot 25=300
\end{aligned}
$$
Larges value $M=750$ and least value $L=120$ Then, $\mathrm{M}-\mathrm{L}=750-120=630$ So, $630=2^1 \cdot 3^2 \cdot 5.7$. Therefore, option (a) is correct.