Let $ a, b \in R $. If the mirror image of the point $ P(a, 6,9) $ with respect to the line $ \frac{x-3}{7}=\frac{y-2}{5}=\frac{z-1}{-9} $ is $ (20, b,-a-9) $, then $ |a+b| $ is equal to:

Question

Let $ a, b \in R $. If the mirror image of the point $ P(a, 6,9) $ with respect to the line $ \frac{x-3}{7}=\frac{y-2}{5}=\frac{z-1}{-9} $ is $ (20, b,-a-9) $, then $ |a+b| $ is equal to:, $ 86 $, $ 90 $, $ 84 $, $ 88 $

MARKS App · Accepted Answer

P 9 , 6 , 9 x - 3 7 = y - 2 5 = z - 1 - 9 Q = 20 , b , - a - 9 20 + a 2 - 3 7 = b + 6 2 - 2 5 = - 9 2 - 1 - 9 14 + 9 14 = b + 2 10 = a + 2 18 ⇒ a = - 56 and b = - 32 ⇒ a + b = 88

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