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Let A be a square matrix of order $\mathrm{n} \times \mathrm{n}$ where $\mathrm{n} \geq 2 .$ Let $\mathrm{B}$ be a matrix obtained from A with first and second rows interchanged. Then which one of the following is correct?
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The correct answer is:
$\operatorname{det} \mathrm{A}=-\operatorname{det} \mathrm{B}$
A be a square matrix of order $\mathrm{n} \times \mathrm{n}$ where $\mathrm{n} \geq 2 . \mathrm{B}$ be a matrix obtained from A with first and second rows interchanged. Then, det $A=-$ det $B$. Since interchanging any two rows makes the sign change with same value.
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