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Let $A$ be the cross-sectional area and $\rho$ be the specific resistance of a potentiometer wire. If $I$ is the current passing through the wire, then the potential gradient along the length of the wire is
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The correct answer is:
$\frac{I \rho}{A}$
Potential gradient $=$ Potential difference per unit length . So,
$k=\frac{V}{L}=\frac{I R}{L}=\frac{I(\rho L / A)}{L}=\frac{I \rho}{A}$
$k=\frac{V}{L}=\frac{I R}{L}=\frac{I(\rho L / A)}{L}=\frac{I \rho}{A}$
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