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Question: Answered & Verified by Expert
Let a=cosθi^-sinθj^, b=sinθi^+cosθj^, c=k^ and r=7ı^+j^+10k^. If r=xa+yb+zc, then the value of x2+y2z is equal to
MathematicsVector AlgebraJEE Main
Options:
  • A 3
  • B 5
  • C 50
  • D 7
Solution:
2844 Upvotes Verified Answer
The correct answer is: 5
r=xcosθ+ysinθi^+-xsinθ+ycosθj^+zk^
r=7ı^+j^+10k^
on comparison
xcosθ+ysinθ=7.i
-xsinθ+ycosθ=1.ii
z=10
Squaring and adding equation i and ii
x2+y2=72+12=50
x2+y2z=5010=5

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