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Question: Answered & Verified by Expert
Let A=cosαsinα-sinαcosα and matrix B is defined such that B=A+3A2+3A3+A4 . If B=8 , then the number of values of α in 0,10π is
MathematicsDeterminantsJEE Main
Options:
  • A 10
  • B 12
  • C 5
  • D 3
Solution:
2535 Upvotes Verified Answer
The correct answer is: 10
B=AI+3A+3A2+A3=AI+A3
B=A  I+A3=8i
A=cosαsinα-sinαcosα=cos2α+sin2α=1
I+A=1+cosαsinα-sinα1+cosα=1+cosα2+sin2α=2+2cosα
From i
12+2cosα3=82+2cosα=2
cosα=0
α=π2,3π2,5π2,7π2,9π2,11π2,13π2,15π2,17π2,19π2
Total number of values =10

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