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Let $A(h, k), B(1,1)$ and $C(2,1)$ be the vertices of a right angled triangle with $A C$ as its hypotenuse. If the area of the triangle is $1$, then the set of values which ' $\mathrm{k}$ ' can take is given by
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Verified Answer
The correct answer is:
$\{-1,3\}$
$\{-1,3\}$
$\frac{1}{2} \times 1(k-1)=\pm 1$
$k-1=\pm 2$
$k=3$
$k=-1$
$k-1=\pm 2$
$k=3$
$k=-1$
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