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Let \(A=\left(\begin{array}{ccc}2 & 0 & 3 \\ 4 & 7 & 11 \\ 5 & 4 & 8\end{array}\right)\). Then
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Verified Answer
The correct answer is:
\(\operatorname{det} A\) is divisible by 11
\(\begin{aligned}
& \text {Hint: } \operatorname{det}(A)=2(56-44)+0+3(16-35) \\
& =24-57 \\
& =-33 \text { which is divisible by } 11
\end{aligned}\)
& \text {Hint: } \operatorname{det}(A)=2(56-44)+0+3(16-35) \\
& =24-57 \\
& =-33 \text { which is divisible by } 11
\end{aligned}\)
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