$\left(A\right)$ $p\vee \left(p\Rightarrow q\right)$ is false only if $p$ is false and $\left(p\Rightarrow q\right)$ is false which is never possible simultaneously. Hence, $p\vee \left(p\Rightarrow q\right)$ is a tautology
$\left(C\right)$ $p\Rightarrow \left(p\vee q\right)$ is false only if $p$ is true and $\left(p\vee q\right)$ is false which is never possible simultaneously. Hence, $p\Rightarrow \left(p\vee q\right)$ is a tautology
$\left(B\right)$ $p\Rightarrow \left(p\wedge q\right)$ is false only if $p$ is true & $p\wedge q$ is false which is possible when $p$ is true & $q$ is false. Hence, $p\Rightarrow \left(p\wedge q\right)$ is not a tautology