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Question: Answered & Verified by Expert
Let $\omega$ be a complex cube root of unity with $\omega \neq 1$ and $P=\left[p_{i j}\right]$ be a $2 \times 2$ matrix with $p_{i j}=\omega^{i+j}$. For $P^2 \neq 0$ if $P^k=P$, then $k$ is equal to
MathematicsMatricesAP EAMCETAP EAMCET 2020 (07 Oct Special)
Options:
  • A 57
  • B 54
  • C 58
  • D 56
Solution:
1490 Upvotes Verified Answer
The correct answer is: 57
No solution. Refer to answer key.

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