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Question: Answered & Verified by Expert
Let ω be the angular velocity of the earth's rotation about its axis. Assume that the acceleration due to gravity on the earth's surface has the same value at the equator and the poles. An object weighed at the equator gives the same reading as a reading taken at a depth d below earth's surface at a pole d<<R. The value of d is
PhysicsGravitationNEET
Options:
  • A ω 2 R 2 g
  • B ω 2 R 2 2 g
  • C 2 ω 2 R 2 g
  • D ω2R24g
Solution:
1760 Upvotes Verified Answer
The correct answer is: ω 2 R 2 g
g eff due to rotation = g eff due to depth d

g - R ω 2 = g 1 - d R R ω 2 = gd R d = R 2 ω 2 g

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