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Question: Answered & Verified by Expert
Let $\alpha$ be the root of the equation $25 \cos ^{2} \theta+5 \cos \theta-12=0$,
where $\frac{\pi}{2} < \alpha < \pi$
What is $\sin 2 \alpha$ equal to?
MathematicsTrigonometric Ratios & IdentitiesNDANDA 2015 (Phase 1)
Options:
  • A $\frac{24}{25}$
  • B $\frac{-24}{25}$
  • C $\frac{-5}{12}$
  • D $\frac{-21}{25}$
Solution:
2502 Upvotes Verified Answer
The correct answer is: $\frac{-24}{25}$
$\sin 2 \alpha=2 \sin \alpha \cdot \cos \alpha$
$=2\left(\frac{3}{5}\right)\left(\frac{-4}{5}\right)$
$=\frac{6}{5} \times \frac{-4}{5}=\frac{-24}{25}$
$\therefore \quad$ Option (b) is correct.

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