Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Let D and E be the midpoints of the sides AC and BC of a triangle ABC respectively. If O is an interior point of the triangle ABC such that OA+2OB+3OC=0, then the area (in sq. units) of the triangle ODE is
MathematicsVector AlgebraJEE Main
Options:
  • A 6
  • B 5
  • C 34
  • D 0
Solution:
2148 Upvotes Verified Answer
The correct answer is: 0

It is given that,

OA+2OB+3OC=0

The figure below represents the triangle ABC and midpoints.

ArODE=12|OD×OE|

=12a+c2×b+c2

=18(a×b+a×c+c×b)  ...i

The given equation can be written as,

a+2b+3c=0  ...ii

Multiply b in equation ii we get,

a×b+2(b×b)+3(c×b)=0

a×b+3(c×b)=0  ...iii

Multiplying c in equation ii we get,

a×c+2(b×c)+3(c×c)=0

a×c+2(b×c)=0  ...iv

Adding equations iii & iv we get,

a×b+3(c×b)+a×c+2(b×c)=0

a×b+a×c+c×b=0

Substituting the above value in equation i we get,

ArODE=0

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.