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Question: Answered & Verified by Expert
Let dxx2+1-x=fx+C such that f0=0 and C is the constant of integration, then the value of f1 is
MathematicsIndefinite IntegrationJEE Main
Options:
  • A 12+12ln1+2
  • B 12+12ln1+2
  • C 12+12ln2+1
  • D 12+121+ln1+2
Solution:
2807 Upvotes Verified Answer
The correct answer is: 12+121+ln1+2
x2+1+x1dx
x2+1dx+xdx
=x2x2+1+12lnx+x2+1+x22+C
fx=x2x2+1+12lnx+1x2+1+x22
f0=0
f1=22+12ln1+2+12=12+121+ln1+2

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