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Question: Answered & Verified by Expert
Let f:AB is a function defined by fx=2x1+x2. If the function fx is a bijective function, then the correct statement can be
MathematicsFunctionsJEE Main
Options:
  • A A=B=-1,1
  • B A=B=-2,2
  • C A=-1,1,B=-2,2
  • D A=-2,2,B=-1,1
Solution:
1884 Upvotes Verified Answer
The correct answer is: A=B=-1,1
fx=2x1+x2
Now, f'x=1+x222x2x1+x2221x21+x22
Clearly,  f x is injective either for x-1,1 or for x-,-11,
Now, for x-1,1
Range of fxf-1,f1-1,1

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