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Question: Answered & Verified by Expert
Let f:R2, be a function defined as fx=x2-12ax+15-2a+36a2. If fx is surjective on R, then the value of a is equal to
MathematicsFunctionsJEE Main
Options:
  • A 92
  • B 112
  • C 132
  • D 152
Solution:
2210 Upvotes Verified Answer
The correct answer is: 132
Rewriting the given function, we get,fx=x-6a2+15-2a
 fx is surjective on R
152a=22a=13a=132

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