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Question: Answered & Verified by Expert
Let f:RR be a differentiable function satisfying f'3+f'2=0. Then limx01+f3+x-f31+f2-x-f21x is equal to
MathematicsLimitsJEE MainJEE Main 2019 (08 Apr Shift 2)
Options:
  • A 1
  • B e
  • C e2
  • D e-1
Solution:
2233 Upvotes Verified Answer
The correct answer is: 1

This limit is 1 form

limx01+f3+x-f31+f2-x-f21x=elimx01x1+f3+x-f31+f2-x-f2-1

=elimx01xf3+x-f3-f2-x+f21+f2-x-f200form

=elimx0 f'3+x+f'2-xx-f'2-x+1+f2-x-f2

=e0=1.

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