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Question: Answered & Verified by Expert
Let f:RR be a function which satisfies fx+y=fx+fy,  x, yR . If f1=2 and gn=k=1n-1fk, nN then the value of n, for which gn=20, is
MathematicsFunctionsJEE MainJEE Main 2020 (02 Sep Shift 2)
Options:
  • A 5
  • B 20
  • C 4
  • D 9
Solution:
1589 Upvotes Verified Answer
The correct answer is: 5

  fx+y=fx+fy

  fx=kx, xR

Now f1=2   k=2

  fx=2x, xR 

gn=f1+f2+..+fn-1

=21+2+3++n-1

=2·n-12n=20

n2-n-20=0 

n=5.

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