Let f x = ∫ 0 x ( t - 1 ) ( t - 2 ) 2 d t . If f x ≥ k for all x and for some k , then the set of exhaustive values of k is

Question

Let f x = ∫ 0 x ( t - 1 ) ( t - 2 ) 2 d t . If f x ≥ k for all x and for some k , then the set of exhaustive values of k is, 0 , ∞, 0 , 2, 1 , ∞, – ∞ , – 17 12

MARKS App · Accepted Answer

x = 1 is a point of global minima of f x Minimum value of f x = ∫ 0 1 t - 1 t - 2 2 d t = ∫ 0 1 t 3 - 5 t 2 + 8 t - 4 d t = - 17 12

Search any question & find its solution

Looking for more such questions to practice?