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Question: Answered & Verified by Expert
Let $f(x)$ be a continuous periodic function with period $T$. Let $I=\int_{a}^{a+T} f(x) d x$. Then
MathematicsDefinite IntegrationWBJEEWBJEE 2021
Options:
  • A $\mathrm{I}$ is linear function in ' $\mathrm{a}$ '
  • B I does not depend on ' $a$ '
  • C $0 < \mathrm{I} < \mathrm{a}^{2}+1$ where $\mathrm{I}$ depends on ' $\mathrm{a}$ '
  • D $\mathrm{I}$ is quadratic function in ' $\mathrm{a}$ '
Solution:
2469 Upvotes Verified Answer
The correct answer is: I does not depend on ' $a$ '
$I=\int_{a}^{a+T} f(x) d x=\int_{0}^{T} f(x) d x$
I does not depend on a.

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