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Question: Answered & Verified by Expert
Let fx be a differentiable function at x=a with f'a=2 and fa=4. Then limxaxfa-afxx-a equals:
MathematicsLimitsJEE MainJEE Main 2021 (26 Feb Shift 2)
Options:
  • A a+4
  • B 2a-4
  • C 4-2a
  • D 2a+4
Solution:
2276 Upvotes Verified Answer
The correct answer is: 4-2a

f'a=2,fa=4

limxaxfa-afxx-a

limxafa-af'x1 (L'Hospitals rule)

=fa-af'a

=4-2a

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