Let f ( x ) = c o s ( x − a ) − c o s ( x + a ) s i n ( x − a ) + s i n ( x + a ) , then-

Question

Let f ( x ) = c o s ( x − a ) − c o s ( x + a ) s i n ( x − a ) + s i n ( x + a ) ​ , then-, f ( x + 2 π ) = f ( x ) but f ( x + α )  = f ( x ) for any 0 α 2 π, f is a strictly increasing function, f is strictly decreasing function, f is a constant function

MARKS App · Accepted Answer

f ( x ) = c o s ( x − a ) − c o s ( x + a ) s i n ( x − a ) + s i n ( x + a ) ​ = 2 s i n x ⋅ s i n a 2 s i n ( x ) ⋅ c o s a ​ = cot a

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