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Question: Answered & Verified by Expert
Let fx=maxx,x2x312-x  3<x12. If S is the set of points in the interval -12,12 at which f is not differentiable, then S is
MathematicsContinuity and DifferentiabilityJEE Main
Options:
  • A equal to -3,3
  • B equal to -3,-1,1,3
  • C an empty set
  • D equal to -3,-1,0,1,3
Solution:
2964 Upvotes Verified Answer
The correct answer is: equal to -3,-1,0,1,3
Here, fx=12+x-12x<-3x2-3x-1x-1<x<1x21x312-x3<x12

Hence, fx is not differentiable at x=-3,-1,0,1,3
S=-3,-1,0,1,3

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