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Question: Answered & Verified by Expert
Let fx=tan3x-3tan2x+1, x-π4,π4. Then, the positive difference between the least value and the local maximum of the function is
MathematicsApplication of DerivativesJEE Main
Solution:
2995 Upvotes Verified Answer
The correct answer is: 4
Let, tanx=tt-1,1 x-π4,π4
ft=t3-3t2+1
f t =3 t 2 6t=3t t2

f-1=-1-3+1=-3
f1=1-3+1=-1
f0=1
Least value =-3
Local maximum value =1
 The positive difference =4

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