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Question: Answered & Verified by Expert
Let fx=x2+2px+2q2 and gx=-x2-2qx+p2 (where q0). If xR and the the minimum value of fx is equal to the maximum value of gx, then the value of p2q2 is equal to 
MathematicsQuadratic EquationJEE Main
Solution:
1895 Upvotes Verified Answer
The correct answer is: 0.5

Since the minimum/maximum value of a quadratic expression ax2+bx+c is given by 4bc-b24a

So, fmin=2q2-p2, gmin=p2+q2
Now, 2q2-p2=p2+q2q2=2p2

Hence, p2q2=12=0.5

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