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Let $\mathrm{f}(\mathrm{x})=[|\mathrm{x}|-\mid \mathrm{x}-1]]^{2}$
What is $\mathrm{f}^{\prime}(\mathrm{x})$ equal to when $\mathrm{x}>1$?
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What is $\mathrm{f}^{\prime}(\mathrm{x})$ equal to when $\mathrm{x}>1$?
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Given $f(x)=(|x|-|x+1|)^{2}$
$f(x)=\left\{\begin{array}{cc}1 & x \leq 0 \\ (2 x-1)^{2} & 0 < x < 1 \\ 1 & x \geq 1\end{array}\right.$
When $x>1$ $f(x)=1$
$f^{\prime}(x)=0$
$f(x)=\left\{\begin{array}{cc}1 & x \leq 0 \\ (2 x-1)^{2} & 0 < x < 1 \\ 1 & x \geq 1\end{array}\right.$
When $x>1$ $f(x)=1$
$f^{\prime}(x)=0$
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