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Let \(f:[1,3] \rightarrow \mathbb{R}\) be continuous and be derivable in \((1,3)\) and \(f^{\prime}(x)=[f(x)]^2+4 \forall x \in(1,3)\). Then
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The correct answer is:
\(f(3)-f(1)=5\) does not hold
\(\begin{aligned}
& \text { Hint : } f^{\prime}(c)=(f(c))^2+4=\frac{f(3)-f(1)}{2} \\
& \Rightarrow f(3)-f(1)=2(f(c))^2+8
\end{aligned}\)
& \text { Hint : } f^{\prime}(c)=(f(c))^2+4=\frac{f(3)-f(1)}{2} \\
& \Rightarrow f(3)-f(1)=2(f(c))^2+8
\end{aligned}\)
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