Let $f(x)=|\sin x|$. Then

Question

Let $f(x)=|\sin x|$. Then, f is everywhere differentiable, $\mathrm{f}$ is everywhere continuous but not differentiable at $\mathrm{x}=\mathrm{n} \pi, \mathrm{n} \in \mathrm{Z}$, $\mathrm{f}$ is everywhere continuous but not differentiable at $\mathrm{x}=(2 \mathrm{n}+1) \frac{\pi}{2}, \mathrm{n} \in \mathrm{Z} \text {. }$, None of these

MARKS App · Accepted Answer

From the graph of $f(x)=|\sin x|$, it is clear that $f(x)$ is continuous everywhere but not differentiable at $x=n \pi, n \in Z$.

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