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Let be a positive integer and a complex number with unit modulus is a solution of the equation , then the value of can be
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Verified Answer
The correct answer is:
Let, satisfies
also satisfies
also satisfies
…
Now, …
From & ,
we get, must be the point of intersection of
&
or {where, is non-real cube root of unity}
can be or
is of the form of
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