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Let $P=(-1,0), Q=(0,0)$ and $R=(3,3 \sqrt{3})$ be three points. Then the equation of the bisector of the $\angle \mathrm{PQR}$ is
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The correct answer is:
$\sqrt{3 x}+y=0$
Given $\mathrm{P}(-1,0), \mathrm{B}=(0,0), R=(3,3 \sqrt{3})$
Now slope of line $Q M=\tan \frac{2 \pi}{3}=-\sqrt{3}$
$\therefore$ Equation of line $Q M=y-\sqrt{3} x=0 \Rightarrow \sqrt{3} x+y=0$
Now slope of line $Q M=\tan \frac{2 \pi}{3}=-\sqrt{3}$
$\therefore$ Equation of line $Q M=y-\sqrt{3} x=0 \Rightarrow \sqrt{3} x+y=0$
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