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Question: Answered & Verified by Expert
Let $P, Q, R$ and $S$ be the points on the plane with position vectors $-2 \hat{\mathbf{i}}-\hat{\mathbf{j}}, 4 \hat{\mathbf{i}}, 3 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}$ an $\mathrm{d}-3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}$ respectively. The quadrilateral $P Q R S$ must be a
MathematicsVector AlgebraJEE AdvancedJEE Advanced 2010 (Paper 1)
Options:
  • A
    parallelogram, which is neither a rhombus nor a rectangle
  • B
    square
  • C
    rectangle, but not a square
  • D
    rhombus, but not a square
Solution:
2259 Upvotes Verified Answer
The correct answer is:
parallelogram, which is neither a rhombus nor a rectangle
$m_{P Q}=\frac{1}{6}, m_{S R}=\frac{1}{6}, \quad m_{R Q}=-3$, $m_{S P}=-3$


$\Rightarrow$ Parallelogram
But neither $P R=S Q$ nor $P R \perp S Q$.
$\therefore$ Parallelogram, which is neither a rhombus nor a rectangle.

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