Let P = θ : sin θ - cos θ = 2 cos θ and Q = θ : sin θ + cos θ = 2 sin θ , be two sets. Then

Question

Let P = θ : sin θ - cos θ = 2 cos θ and Q = θ : sin θ + cos θ = 2 sin θ , be two sets. Then, P ⊂ Q and Q - P ≠ ϕ, Q ⊄ P, P = Q, P ⊄ Q

MARKS App · Accepted Answer

P : sin θ - cos θ = 2 cos θ ⇒ sin θ = cos θ + 2 cos θ tan θ = 2 + 1 Q : sin θ + cos θ = 2 sin θ ⇒ 2 - 1 sin θ = cos θ = tan θ = 1 2 - 1 = 2 + 1