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Question: Answered & Verified by Expert
Let S, be the set of all functions f:0,1R, which are continuous on 0,1, and differentiable on 0,1. Then for every f in S, there exists c0,1, depending on f, such that.
MathematicsContinuity and DifferentiabilityJEE MainJEE Main 2020 (08 Jan Shift 2)
Options:
  • A fc-f1<1-cf'c
  • B f1-fc1-c=f'c
  • C fc+f1<1+cf'c
  • D fc-f1<f'c
Solution:
2882 Upvotes Verified Answer
The correct answer is: f1-fc1-c=f'c

Let us consider fx, a constant function, as constant functions are continuous and differentiable everywhere.

Then, f1=fc & f'c=0

So, f1-fc1-c=f'c=0.

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