Let S = x ∈ R : x ≥ 0 & 2 x - 3 + x x - 6 + 6 = 0 . Then S :

Question

Let S = x ∈ R : x ≥ 0 & 2 x - 3 + x x - 6 + 6 = 0 . Then S :, Contains exactly four elements, Is an empty set, Contains exactly one element, Contains exactly two elements

MARKS App · Accepted Answer

2 x - 3 + x x - 6 + 6 = 0 Let x = t > 0 2 t - 3 + t t - 6 + 6 = 0 ⇒ 2 t - 3 = - t 2 - 6 t + 6 ⇒ 2 t - 3 = - t 2 - 6 t + 9 + 3 So the equation 2 solutions.

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