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Question: Answered & Verified by Expert
Let the equation of a line is x-21=y-32=z-43. An insect starts flying from P1,3,2 in a straight line meeting the given line at a point Ra,b,c and then goes to the point Q6,7,5 in a straight line such that PR is perpendicular to RQ. Then, the least value of 7a+b+c is equal to
MathematicsThree Dimensional GeometryJEE Main
Options:
  • A 105
  • B 45
  • C 10
  • D 7
Solution:
2710 Upvotes Verified Answer
The correct answer is: 45

Any general point on the line is λ+2,2λ+3,λ+4

PR=<λ+1,2λ,3λ+2>
RQ=<4-λ,4-2λ,1-3λ>
From the diagram, PRRQ=0

λ+14λ+2λ42λ+3λ+213λ=0
λ2-3λ-4+4λ2-8λ+9λ2+3λ-2=0
14λ2-8λ-6=0
λ=1,-37
Coordinates of R are 3,5,7 or 117,157,197
Least value of 7a+b+c=11+15+19=45

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