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Question: Answered & Verified by Expert
Let the equation of the pair of lines, y=px and y=qx, can be written as y-pxy-qx=0. Then the equation of the pair of the angle bisectors of the lines x2-4xy-5y2=0 is:
MathematicsStraight LinesJEE MainJEE Main 2021 (25 Jul Shift 2)
Options:
  • A x2-3xy+y2=0
  • B x2+4xy-y2=0
  • C x2+3xy-y2=0
  • D x2-3xy-y2=0
Solution:
1298 Upvotes Verified Answer
The correct answer is: x2+3xy-y2=0

We have, equation of a pair of lines x2-4xy-5y2=0

Now, equation of bisector of a pair of lines x2-y21--5=xy-2

x2-y26=xy-2

x2-y2=-3xy

x2+3xy-y2=0.

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