Let the initial concentration of P is 1 M, the concentration of P after 33.33 sec is equal to?

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Question: Answered & Verified by Expert

Let the initial concentration of P is 1 M, the concentration of P after 33.33 sec is equal to?

ChemistryChemical KineticsJEE Main

Options:

A $\frac{1}{e}$
B $\frac{2}{e}$
C $\frac{1}{e^{2}}$
D $e$

Solution:

2946 Upvotes Verified Answer

The correct answer is:

\frac{1}{e}

$k_{eff} = k_{1} + k_{2}$

${(P)}_{t} = 1 \times e^{- k t}$
$= e^{- 3 \times 1 0^{- 2} \times 33.3}$
$= e^{- 0.99} = \frac{1}{e}$

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