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Let the length of the latus rectum of an ellipse with its major axis along $x$ -axis and centre at the origin, be 8 . If the distance between the foci of this ellipse is equal to the length of its minor axis, then which one of the following points lies on it?
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The correct answer is:
$(4 \sqrt{3}, 2 \sqrt{2})$
Let the ellipse be $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$
Then, $\frac{2 b^{2}}{a}=8,2 a e-b^{2}$ and $b^{2}=a^{3}\left(1-e^{2}\right)$
$\Rightarrow a=8, b^{2}=32$
Then, the equation of the ellipse
$\frac{x^{2}}{64}+\frac{y^{2}}{32}=1$
Hence, the point $(4 \sqrt{3}, 2 \sqrt{2})$ lies on the ellipse.
Then, $\frac{2 b^{2}}{a}=8,2 a e-b^{2}$ and $b^{2}=a^{3}\left(1-e^{2}\right)$
$\Rightarrow a=8, b^{2}=32$
Then, the equation of the ellipse
$\frac{x^{2}}{64}+\frac{y^{2}}{32}=1$
Hence, the point $(4 \sqrt{3}, 2 \sqrt{2})$ lies on the ellipse.
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