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Question: Answered & Verified by Expert
Let there are exactly two points on the ellipse x2a2+y2b2=1 whose distances from 0,0 are equal to a22+b2. Then, the eccentricity of the ellipse is equal to
MathematicsEllipseJEE Main
Options:
  • A 12
  • B 122
  • C 12
  • D None of these
Solution:
2869 Upvotes Verified Answer
The correct answer is: 12
Since, a22+b2>b
Hence, major axis =2a & minor axis =2b and a22+b2=aa22+b2=a2
b2=a22b2a2=12
1-e2=12e2=12=e=12

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