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Question: Answered & Verified by Expert
Let x1,x2,,x100 be in an arithmetic progression, with x1=2 and their mean equal to 200 . If yi=ixi-i,1i100, then the mean of y1,y2,, y100 is
MathematicsSequences and SeriesJEE MainJEE Main 2023 (11 Apr Shift 1)
Options:
  • A 10100
  • B 10101.50
  • C 10049.50
  • D 10051.50
Solution:
1725 Upvotes Verified Answer
The correct answer is: 10049.50

Given,

Mean of x1, x2..........,x100 is 200

So, the sum of observation will be,

xi=100×200

Now using the sum of A.P formula in above equation as all terms are in arithmetic progression we get,

1002x1+x100=100×200

502+x100=100×200

x100=398

x1+99d=398

d=4

Now, xi=2+(i-1)4=4i-2

So, yi=ixi-i=3i2-2i

Now finding mean we get,

y¯=1100yi

y¯=11003i2-2i

y¯=11003×100×101×2016-2100×1012

y¯=101×2012-101

y¯=10049.5

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