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Question: Answered & Verified by Expert
Let x2=4ky,k>0 be a parabola with vertex A. Let BC be its latusrectum. An ellipse with centre on BC touches the parabola at A, and cuts BC at points D and E such that BD=DE=EC (B, D, E, C in that order). The eccentricity of the ellipse is
MathematicsEllipseJEE Main
Options:
  • A 12
  • B 13
  • C 53
  • D 32
Solution:
2183 Upvotes Verified Answer
The correct answer is: 53

Given, x2=4ky



BC is latusrectum.


BC=4k


BD=DE=EC


DE=BC3=4k3


P is centre of ellipse.


PE=2k3


OP=k


Eccentricity of ellipse


1-PE2OP2=1-4k29k2


e=9-49=53


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