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Question: Answered & Verified by Expert
Let xk+yk=ak,a,k>0 and dydx+yx13=0, then k is
MathematicsDifferentiationJEE MainJEE Main 2020 (07 Jan Shift 1)
Options:
  • A 32
  • B 43
  • C 23
  • D 13
Solution:
2252 Upvotes Verified Answer
The correct answer is: 23
Differentiating the given equation with respect to x

k.xk-1+k.yk-1dydx=0

dydx=-xyk-1

dydx+xyk-1=0

k-1=-13

k=1-13=23

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