Let y = 1 + x + l n x 1 , Then, x d x d y + y = x, x d x d y = y ( y ln x − 1 ), x 2 d x d y = y 2 + 1 − x 2, x ( d x d y ) 2 = y − x

Hint: x d x d y = y ( y ln x − 1 )

Let y = 1 + x + l n x 1 , Then

Question: Answered & Verified by Expert

Let $\mathrm{y}=\frac{1}{1+\mathrm{x}+\ln \mathrm{x}}$, Then

MathematicsDifferential EquationsWBJEEWBJEE 2020

Options:

Solution:

1368 Upvotes Verified Answer

The correct answer is: $x \frac{d y}{d x}=y(y \ln x-1)$

Hint:
$x \frac{d y}{d x}=y(y \ln x-1)$

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