Let Z denote the set of integers define f : Z → Z by f ( x ) = { 2 x , 0 , x is even x is odd then f is

Question

Let Z denote the set of integers define f : Z → Z by f ( x ) = { 2 x ​ , 0 , ​ x is even x is odd ​ then f is, onto but not one-one, one-one but not onto, one-one and onto, neither one-one nor onto

MARKS App · Accepted Answer

Clearly, it is onto but not one-one. Since each odd integer mapped with zero.

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